Why does var replacement not work in snippet?

[henk_stobbe]

Hello.

I have defined two vars:

and

Using this snippet:

export default async function ()
{
return $Varx
}

Why does var2 (text) work?

But var2 (CSV) not?

KR Henk

[henk_stobbe · Accepted solution]

Simple solution,

Delete filter and start over (-:

If the default value does not appear, you have the same issue!

KR Henk